WebWhat will be the output of the following R code? x <- 1:3 y <- 10:12 cbind(x, y) a) x y [1,] 6 10 2,] 7 11[ 3,] 8 12 b) x y [1,] 1 10 [2,] 2 11 [3,] 3 12 c) x y[ 1,] 1 4[ 2,] 2 5[ 3,] 3 6 d) x y [1,] 1 6[ … WebDraw a dendrogram that is equivalent to the dendrogram in (a), for which two or more of the leaves are repositioned, but for which the meaning of the dendrogram is the same. plot …

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WebAug 4, 2016 · If X 1 and X 2 are two jointly distributed random variables, then the conditional distribution of X 2 given X 1 is itself normal with: mean = m2 + r ( s2 / s1 ) (X 1 – m 1) and variance = (1 – r2) s2 X 2. Hence, a sample from a bivariate Normal distribution can be simulated by first simulating a point from the marginal distribution of one ... Web> x <- 3 > switch(x, 2+2, mean(1:10), rnorm(5)) [1] 2.2903605 2.3271663 -0.7060073 1.3622045 -0.2892720 > switch(2, 2+2, mean(1:10), rnorm(5)) [1] 5.5 > switch(6, 2+2, … christina zhang dji

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Webx <- rnorm(n = 10, mean = 10, sd = 4) describe(x) And then, if we do this again: set.seed(1) y <- rnorm(n = 10, mean = 10, sd = 4) describe(y) Then we get the same values again. You … WebMar 24, 2015 · We'll start with basic integration. Suppose we have an instance of a Normal distribution with a mean of 1 and a standard deviation of 10. Then we want to find the … Web> x <- 3 > switch(x, 2+2, mean(1:10), rnorm(5)) a. 2.2903605 2.3271663 -0.7060073 1.3622045 -0.2892720: b. 5.5: c. NULL: d. Error: ... _____ function generates “n” normal … christina zikeli