Predicting equilibrium shift
http://chemvision.net/102_Lab_5_LeChateliers_Sp19.pdf Webequilibrium (MPE) is a subgame-perfect equilibrium (SPE) in which agents use Markov strategies. In an RPD, if choices are forced to be history independent then there is a unique equilibrium: playing the stage-game Nash equilibrium in all periods. 16The strategy here is ‘best case’ in three senses: (i) It can support the best-case outcome.
Predicting equilibrium shift
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http://dept.harpercollege.edu/chemistry/chm/100/dgodambe/thedisk/equil/8back4.htm
WebTo re-establish equilibrium, the system will either shift toward the products (if Q < K) or the reactants (if Q > K) until Q returns to the same value as K. This process is described by Le … Weball components must change. One way of predicting these concentration shifts is through the use of Le Chatelier's principle: When a stress is applied to a system at equilibrium (a change in concentrations, temperature, pressure, volume), the system will shift in the direction that reduces the stress and return unaided to a new equilibrium.
Webgiven reaction at equilibrium and at a constant temperature. ⇒ The equilibrium concentrations of reactants and products may vary, but the value for K c remains the same. Other Characteristics of Kc 1) Equilibrium can be approached from either direction. 2) K c does not depend on the initial concentrations of reactants and products. 3) K WebQuite useful for predicting what will happen under special conditions. Exercise 7 Using the Reaction Quotient For the synthesis of ammonia at 500°C, the equilibrium constant is 6.0 × 10-2. Predict the direction in which the system will shift to reach equilibrium in each of the following cases: a. [NH3]0 = 1.0 × 10-3 M; [N 2]0 = 1.0 × 10
WebWhat will be the equilibrium constant of the Chemical equilibrium at 500 o C if the heat of the reaction at this temperature range is -25.14 kcal? Solution: Equilibrium constants at different temperature and heat of the reaction are related by the equation, log KP 2 = -25140/2.303 × 2 [773 – 673 / 773 × 673] + log 1.64 × 10-4. log KP 2 ...
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